Question bank/JEE Main/Mathematics
JEE MainMathematicsEasyPermutations and Combinations
The sum of all the 4 digits numbers formed using digits 0,2,3,5
(repetition is not allowed) is equal to
Show answer and solution
Sum of all four digit numbers formed = sum of all numbers - sum
of numbers with 0 in the first place
Sum of all the numbers = 6(2+3+5+0)(1000+100+10+1)= 66660
Sum of numbers with 0 in the first place = 2(2+3+5) (100+10+1) = 2220
Hence, the answer = 66660 - 2220 = 64440
of numbers with 0 in the first place
Sum of all the numbers = 6(2+3+5+0)(1000+100+10+1)= 66660
Sum of numbers with 0 in the first place = 2(2+3+5) (100+10+1) = 2220
Hence, the answer = 66660 - 2220 = 64440
Source: Grass-G / M-10 Mathematics Paper-1 30 Oct.docx
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