Question bank/JEE Main/Mathematics

JEE MainMathematicsToughLimits, continuity and derivability

The function f(x) = maximum
{x(2−x),2−x}\left\{ \sqrt{x(2 - x)},2 - x \right\} is non-differentiable at x
equal to

Show answer and solution
[IMAGE] At x = 2
L.H.D
=h→Lt0+(2−h)(2−(2−h))−0−h= h\overset{Lt}{\rightarrow}0^{+}\frac{\sqrt{(2 - h)(2 - (2 - h))} - 0}{- h}
=h→Lt0+2−h−h(20 form )= h\overset{Lt}{\rightarrow}0^{+}\frac{\sqrt{2 - h}}{- \sqrt{h}}\left( \frac{\sqrt{2}}{0}\ form\ \right)
= not finite.

Source: Grass-G / M-11 Mathematics Paper-2 1Nov.docx

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