Question bank/JEE Main/Mathematics
JEE MainMathematicsEasyPemutation and combination
There are 5 girls and 7 boys. A team of 3 boys and 2 girls is to
be formed such that no two specific boys are in the same team. Number of
way to do so
Show answer and solution
Without any restriction, total number of ways of forming team
is If two specific boys B_1,
B_2 are in same team then total number of ways of forming team equals
to ways total ways = 350 - 50 =
300 ways.
is If two specific boys B_1,
B_2 are in same team then total number of ways of forming team equals
to ways total ways = 350 - 50 =
300 ways.
Source: Grass-G / M-11 Mathematics Paper-2 1Nov.docx
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