JEE MainMathematicsEasyIndefinite integration

If c is arbitrary constant
then $\int\frac{\left( x^{8} + 4 \right)dx}{x^{4} - 2x^{2} + 2} =$

Show answer and solution

\Rightarrow \int\frac{\left( x^{8} + 4 + 4x^{4} \right) - 4x^{4}}{x^{4} - 2x^{2} + 2}dx = \int\frac{\left( x^{8} + 2x^{2} + 2 \right)\left( x^{4} - 2x + 2 \right)}{\left( x^{4} - 2x^{2} + 2 \right)}dx = \frac{x^{5}}{5} + \frac{2x^{3}}{3} + 2x + c

Source: Grass-G / M-12 Mathematics Paper 2 Nov.docx

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