If the range of the function on the interval be then the value of 5 b - 2 a =.

JEE MainMathematicsModerateMonotonocity

If the range of the function $y = \frac{x - 1}{x + 1}$ on the
interval $0 \leq x \leq 4$ be then the value of 5 b - 2 a =.

Show answer and solution

\frac{dy}{dx} = \frac{2}{(x + 1)^{2}} > 0

That means is entirely increasing in
Hence the function is minimum at x = 0, with y = -1 and is maximum at
x = 4 with y = 3/

Source: Grass-G / M-12 Mathematics Paper 2 Nov.docx

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