Question bank/JEE Main/Mathematics

JEE MainMathematicsEasyDifferentiation

If x=acos⁡3t,y=bsin⁡3t,x = a\cos^{3}t,y = b\sin^{3}t, then dydx=\frac{dy}{dx} =

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dydx=yx=−batan⁡ t \frac{dy}{dx} = \frac{y}{x} = - \frac{b}{a}\tan\ t\

Source: Grass-G / M-12 Mathematics Paper 2 Nov.docx

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