If the order and degree of differential equation respectively are a & b then value of 2a^2b.

JEE MainMathematicsEasyDifferential equation

If the order and degree of differential equation
$\left\lbrack 1 + \left( \frac{dy}{dx} \right)^{2} \right\rbrack^{5/2} = x\frac{d^{3}y}{dx^{3}}$
respectively are a & b then value of 2a^2b.

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Here

\left\lbrack 1 + \left( \frac{dy}{dx} \right)^{2} \right\rbrack^{5} = x^{2}\left( \frac{d^{3}y}{dx^{3}} \right)^{2}

\therefore

Order = 3, degree = 2

Source: Grass-G / M-13 Mathematics Paper 4 Nov.docx

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