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JEE MainMathematicsEasyDifferential Equation
The solution of differential equation (ex + 1) y dy = (y + 1)
e^x dx is.
Show answer and solution
The given differential equation is (e^x + 1) y dy = (y + 1)
e^x dx
dx; Integrating both sides
y - log |y + 1| = log (e^x + 1) + log k
y = log |(y + 1)(e^x + 1)| + log k
(y + 1)(e^x + 1) = e^yc
e^x dx
dx; Integrating both sides
y - log |y + 1| = log (e^x + 1) + log k
y = log |(y + 1)(e^x + 1)| + log k
(y + 1)(e^x + 1) = e^yc
Source: Grass-G / M-13 Mathematics Paper 4 Nov.docx
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