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JEE MainMathematicsModerateSequences and Series

7^th term of an AP is 40, then the sum of first 13 terms is

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S13=132[2a+12d]S_{13} = \frac{13}{2}\lbrack 2a + 12d\rbrack
=13×T7= 13 \times T_{7}
= 520

Source: Grass-G / M-16 Mathematics Paper 25 Nov First.docx

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