Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateSequences and Series

In a G.P., if (2p)th(2p)^{th} term is q2q^{2} and (2q)th(2q)^{th} term
is
p2p^{2} where p and q∈Np\ and\ q \in N, then its (p+q)th(p + q)^{th} term is

Show answer and solution
q2=AR2p−1andp2=QR2q−1q^{2} = {AR}^{2p - 1}andp^{2} = QR^{2q - 1}
Tp+q=ARp+q−1=(AR2p−1⋅AR2q−1)1/2T_{p + q} = AR^{p + q - 1} = {(AR^{2p - 1} \cdot AR^{2q - 1})}^{1/2}
=(p2q2)1/2=pq= {(p^{2}q^{2})}^{1/2} = pq

Source: Grass-G / M-16 Mathematics Paper 25 Nov First.docx

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.