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JEE MainMathematicsEasyLogarithm

If logx2=logy3=logz5,\frac{logx}{2} = \frac{logy}{3} = \frac{logz}{5}, then
x2=x^{2} =

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logx2=logy3=logz5\frac{logx}{2} = \frac{logy}{3} = \frac{logz}{5} then
x1/2=Kx^{1/2} = K
y1/3=K,z1/5=Ky^{1/3} = K,z^{1/5} = K
⇒x=K2,y=K3,z=K5⇒x2=K4\Rightarrow x = K^{2},y = K^{3},z = K^{5} \Rightarrow x^{2} = K^{4}
yz=K8=K4⇒x2=yz\sqrt{yz} = \sqrt{K^{8}} = K^{4} \Rightarrow x^{2} = \sqrt{yz}

Source: Grass-G / M-16 Mathematics Paper 25 Nov First.docx

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