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JEE MainMathematicsEasyITF

Let
f(x)=x105+x53+x27+x13+x3+3x+1f(x) = x^{105} + x^{53} + x^{27} + x^{13} + x^{3} + 3x + 1. If g(x) is
inverse of function f(x), then the value of
9g′(1)9g^{'}(1) is

Show answer and solution
since g(x) is inverse of f(x)
g(f(x))=xg(f(x)) = x
Differentiating w.r.t. x

g′(f(x))⋅f′(x)=1g^{'}(f(x)) \cdot f^{'}(x) = 1
x=0,f(0)=1x = 0,f(0) = 1
∴g′(f(0))⋅f′(0)=1\therefore g^{'}(f(0)) \cdot f^{'}(0) = 1
g′(1)=1f′(0)g^{'}(1) = \frac{1}{f^{'}(0)}
∴f′(0)=3)∴g′(1)=13\begin{matrix} \therefore f^{'}(0) = 3) & \therefore & g^{'}(1) = \frac{1}{3} \end{matrix}

Source: Grass-G / M-17 Mathematics Paper 26 Nov Second.docx

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