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JEE MainMathematicsEasyTrigonometry

The number of values of x in the interval satisfying
the equation 3sin^2x - 7 sin x + 2 = 0 is

Show answer and solution
(s - 2)(3s - 1) = 0
⇒s=1/3=sinα,\Rightarrow s = 1/3 = sin\alpha, say 
x=nπ+(−1)nα,n=0,1,2,3,4,5in(0,5π)x = n\pi + ( - 1)^{n}\alpha,n = 0,1,2,3,4,5in(0,5\pi)

Source: Grass-G / M-18 Mathematics Paper 27 Nov Third.docx

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