Question bank/JEE Main/Mathematics

If $\ \frac{z - (1 + i)}{z + (1 + i)}$ is purely imaginary
then z lies on a circle. Find radius of circle

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$\frac{z - (1 + i)}{z + (1 + i)} + \frac{\overset{¯}{z} - (1 - i)}{\overset{¯}{z} + (1 - i)} = 0$
[IMAGE] So locus is a circle.

Source: Grass-G / M-18 Mathematics Paper 27 Nov Third.docx