JEE MainMathematicsModerateStraight Lines

The distance of point of intersection of lines represented by the
equation
$2x^{2} - 10xy + 12y^{2} + 5x - 16y - 3 = 0$ from origin is

Show answer and solution

Given equation of pair of straight line is

2x^{2} - 10xy + 12y^{2} + 5x - 16y - 3 = 0

point of intersection is

A\left( - 10, - \frac{7}{2} \right)

\therefore

distance

OA = \sqrt{100 + \frac{49}{4}} = \sqrt{\frac{449}{4}}

Source: Grass-G / M-19 Mathematics Paper 28 Nov Fourth.docx

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