JEE MainMathematicsEasyLimits

$\lim_{x \rightarrow 0}\mspace{2mu}\frac{\sqrt{1 - cos2x}}{x} =$

Show answer and solution

\lim_{x \rightarrow 0}\mspace{2mu}\frac{\sqrt{2}|sinx|}{x}

L.H.L

= - \sqrt{2}

R.H.L.

= \sqrt{2}

Both are not equal.

Source: Grass-G / M-19 Mathematics Paper 28 Nov Fourth.docx

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