JEE MainMathematicsModerateSequences and Series

n, G.M.'s are inserted between two numbers 2 and 162. If the
product of the n G.M.'s is 5832 then n is

Show answer and solution

Product of n, G.M.'s

n = (2.162)^{\frac{n}{2}}

(324)^{\frac{n}{2}} = 5832

18^n = 5832
18^n = 18^3
n = 3

Source: Grass-G / M-19 Mathematics Paper 28 Nov Fourth.docx

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