If at x = e is equal to

JEE MainMathematicsModerateDifferentiation

If $y = (\mathcal{l}nx)^{x},\ then\ \frac{dy}{dx}$ at x = e is
equal to

Show answer and solution

\frac{dy}{dx}\mathcal{= (l}nx)^{x}\left( \mathcal{l}n(\mathcal{l}nx) + \frac{1}{\mathcal{(l}nx} \right)

\left( \frac{dy}{dx} \right)_{x = e} = 1

Source: Grass-G / M-19 Mathematics Paper 28 Nov Fourth.docx

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