Question bank/JEE Main/Mathematics

Value of $\lambda$ so that point
$\left( \lambda,\lambda^{2} \right)$ lies between the lines
$|x + 2y| = 3$ is

A$\left( - \frac{1}{2},2 \right)$B$\left( - \frac{3}{2},2 \right)$C$\left( - \frac{3}{2},1 \right)$D$\left( - 1,\frac{3}{2} \right)$

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$2\lambda^{2} + \lambda - 3 < 0$
$\lambda \in \left( - \frac{3}{2},1 \right)$

Source: Grass-G / M-19 Mathematics Paper 28 Nov Fourth.docx