Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateLimits

lim⁡x→0\mspace2muln(tan(π4+ax))sinbx,b≠0\lim_{x \rightarrow 0}\mspace{2mu}\frac{ln\left( tan\left( \frac{\pi}{4} + ax \right) \right)}{sinbx},b \neq 0
is equal to

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lim⁡x→0\mspace2muln(tan(π4+ax))sinbx,b≠0\lim_{x \rightarrow 0}\mspace{2mu}\frac{\mathcal{l}n\left( tan\left( \frac{\pi}{4} + ax \right) \right)}{sinbx},b \neq 0
lim⁡x→0\mspace2muln(1+2tanax1−tanax)⋅(2tanax1−tanax)(bx)(2tanax1−tanax)sinh(bx)\lim_{x \rightarrow 0}\mspace{2mu}\frac{\mathcal{l}n\left( 1 + \frac{2tanax}{1 - tanax} \right) \cdot \left( \frac{2tanax}{1 - tanax} \right)(bx)}{\left( \frac{2tanax}{1 - tanax} \right)}sinh(bx)
lim⁡x→0\mspace2mu2tanaxbx=2ab\lim_{x \rightarrow 0}\mspace{2mu}\frac{2tanax}{bx} = \frac{2a}{b}

Source: Grass-G / M-19 Mathematics Paper 28 Nov Fourth.docx

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