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JEE MainMathematicsToughApplication of derivatives

If a variable tangent to the curve x2y=c3x^{2}y = c^{3} makes
intercepts a, b on x and y axis respectively, then the value of
a2ba^{2}b
is

Show answer and solution
x2y=c3x^{2}y = c^{3} ⇒y=c3x2\Rightarrow y = \frac{c^{3}}{x^{2}}
⇒dydx=−2c3x3\Rightarrow \frac{dy}{dx} = - \frac{2c^{3}}{x^{3}}
Variable tangent:

(y−y1)=−2c3x13(x−x1)(y - y_{1}) = - \frac{2c^{3}}{x_{1}^{3}}(x - x_{1})
a=y1x132c3+x1a = \frac{y_{1}x_{1}^{3}}{2c^{3}} + x_{1} =x12+x1= \frac{x_{1}}{2} + x_{1}
=3x12= \frac{3x_{1}}{2}
b=y1+2c3x12=3c3x12b = y_{1} + \frac{2c^{3}}{x_{1}^{2}} = \frac{3c^{3}}{x_{1}^{2}}
⇒a2b=94x12×3c3x12=274c3\Rightarrow a^{2}b = \frac{9}{4}x_{1}^{2} \times \frac{3c^{3}}{x_{1}^{2}} = \frac{27}{4}c^{3}

Source: Grass-G / M-20 Mathematics Paper 12 Dec.docx

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