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Mr. A lives at origin on the cartesian plane and has his office
at (4, 5). His friend lives at (2, 3) on the same plane. Mr. A can go to
his office travelling one block at a time either in the + y or + x
direction. If all possible paths are equally likely then the probability
that Mr. A passed his friends house is.
Jheku~ A dkrhZ; lery ij ewy fcUnq ij jgrs gS rFkk mudk vkWfQl (4, 5).;k + x,d CykWd =kk dj muds vkWfQl tk ldrs gSA;fn
lHkh iFk lelEHkkfor gks rks Jheku~ A ds vius fe=

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Total number of ways
$= = \frac{9 \times 8 \times 7 \times 6}{24} = 21 \times 6$
[IMAGE] Number of ways [IMAGE] Probability $= \frac{10 \times 6}{21 \times 6} = \frac{10}{21}$

Source: Grass-G / M-21 Mathematics Paper 19 Dec Hindi Eng.docx