Question bank/JEE Main/Mathematics

[IMAGE] are three non coplanar vectors. If
[IMAGE] is perpendicular to [IMAGE], then
minimum value of x^2 + y^2 is.
yEcor~ rksa x^2 + y^2 eku gS&

ANone of these buesa

Show answer and solution▾

[IMAGE] sin x + cos y = -2
This is possible only when sin x = - 1 and cos y = -1
for x^2 + y^2 to be minimum x = - $\frac{\pi}{2}$ and
$y = \pi$[IMAGE] minimum value of
$\left( x^{2} + y^{2} \right)\ is\$
gy [IMAGE] sin x + cos y = -2;g rHkh lEHko gS tcsin x = - 1 vkSjcos y = -1
x^2 + y^2 gksus ds fy, x = - $\frac{\pi}{2}$vkSj $y = \pi$
[IMAGE] (x^2 + y^2)

Source: Grass-G / M-21 Mathematics Paper 19 Dec Hindi Eng.docx