Question bank/JEE Main/Mathematics

A vector [IMAGE] of magnitude $20\sqrt{6}$
parallel to the bisector of the angle between [IMAGE] and

A$\pm \frac{20}{3}(î - 7ĵ + 2ƙ)$

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A vector along the bisector is $\therefore$ The required vectors are vHkh"V lfn'k gksaxs
$$\pm + 49 + - 7ĵ + 2ƙ)$$

Source: Grass-G / M-21 Mathematics Paper 19 Dec Hindi Eng.docx