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JEE MainMathematicsToughSpecial functions

If the fractional part of the number
240315\frac{2^{403}}{15} is k15\frac{k}{15},then k is equal to

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{220315}\left\{ \frac{2^{203}}{15} \right\}
8.2^200
⇒\Rightarrow 8.16^50 = 8(1 + 15)^50 = 8(1 + 15)
Hence remainder is

Source: Grass-G / M-22 Mathematics Paper 19 Dec Eng.docx

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