Question bank/JEE Main/Mathematics
JEE MainMathematicsEasyInequalities
Number of integral values of m for which the inequality
is satisfied by all real
values of x.
Show answer and solution
Given > - 1 for
all
x^2 - mx - 2 > - (x^2 - 3x + 4) (as x^2 -
3x + 4 > 0 x R)
for all x R
disc. = (m + 3)^2 - 16 < 0
m^2 + 6x - 7 < 0
(m + 7) (m - 1) < 0
m (-7, 1)
no. of integral values of m is 7
all
x^2 - mx - 2 > - (x^2 - 3x + 4) (as x^2 -
3x + 4 > 0 x R)
for all x R
disc. = (m + 3)^2 - 16 < 0
m^2 + 6x - 7 < 0
(m + 7) (m - 1) < 0
m (-7, 1)
no. of integral values of m is 7
Source: Grass-G / M-23 Mathematics Paper 31 Dec FST.docx
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