Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateTheory of Equations

The set of value of if the equation x^3 - 3x^2 + 2 = k
has only 1 real root is equal to
(−∞,a)∪(b,∞)( - \infty,a) \cup (b,\infty). Find
value of
∣10ab∣3\frac{|10ab|}{3}

Show answer and solution
The graph of f(x) = (x^3 -3x^2 + 2) is
[IMAGE] Hence, for 1 real root of given equation will exist when

K∈(−∞,−2)∪(2,∞)K \in ( - \infty, - 2) \cup (2,\infty)
∴\therefore a = - 2 b = 0

Source: Grass-G / M-23 Mathematics Paper 31 Dec FST.docx

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