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JEE MainMathematicsModerateArea under curve

The area of the curve enclosed by 2∣x∣+3∣y∣≤62|x| + 3|y| \leq 6 is given
by the value of
(4A+85)\left( \frac{4A + 8}{5} \right) equals to

Show answer and solution
Diagram of curve 2∣x∣+3∣y∣≤62|x| + 3|y| \leq 6
[IMAGE] The shaded region will represent the area enclosed by given curve and

it is a square so and (PQRS) =
6×42\frac{6 \times 4}{2} = 12 units = A

Source: Grass-G / M-23 Mathematics Paper 31 Dec FST.docx

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