Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateSequences and Series

If sum of all terms of an infinite GP is 15\frac{1}{5} times the
sum of odd terms. Then, common ratio is

Show answer and solution
Let S denotes the sum of all terms and S_1 denotes the sum of
odd terms.

S1=a1−r2S_{1} = \frac{a}{1 - r^{2}} (i.e. sum of odd terms)
Given,

S=15S1⇒a1−r=15×a1−r2S = \frac{1}{5}S_{1} \Rightarrow \frac{a}{1 - r} = \frac{1}{5} \times \frac{a}{1 - r^{2}}
⇒1+r=15⇒r=−45\Rightarrow 1 + r = \frac{1}{5} \Rightarrow r = - \frac{4}{5}

Source: Grass-G / M-23 Mathematics Paper 31 Dec FST.docx

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