Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateComplex Numbers

If z_1, z_2, z_3 are three points lying on the circle |z| =
2 then the minimum value of

∣z1+z2∣2+∣z2+z3∣2∣z3+z1∣2\left| z_{1} + z_{2} \right|^{2} + \left| z_{2} + z_{3} \right|^{2}\left| z_{3} + z_{1} \right|^{2}
is equal to

Show answer and solution
∣z1+z2∣2+∣z2+z3∣2+∣z3+z1∣2\left| z_{1} + z_{2} \right|^{2} + \left| z_{2} + z_{3} \right|^{2} + \left| z_{3} + z_{1} \right|^{2}
=2(∣z1∣2+∣z2∣2+∣z3∣2)\mathbf{=}2\left( \left| z_{1} \right|^{2} + \left| z_{2} \right|^{2} + \left| z_{3} \right|^{2} \right)+(z1z2→+z2z1→+z2z3→+z3z2→+z3z1→+z1z3→)\left( z_{1}\overrightarrow{z_{2}} + z_{2}\overrightarrow{z_{1}} + z_{2}\overrightarrow{z_{3}} + z_{3}\overrightarrow{z_{2}} + z_{3}\overrightarrow{z_{1}} + z_{1}\overrightarrow{z_{3}} \right)


Source: Grass-G / M-23 Mathematics Paper 31 Dec FST.docx

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