If = a^2 - (b-c)^2, then tan A is

JEE MainMathematicsModerate

If $\Delta$ = a^2 - (b-c)^2, then tan A is

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\Delta

= (a + b - c) (a - b + c) = 2( s - c). 2 (s - b)

\Delta

= 4(s - b) (s - c)

\ \frac{(s - b)(s - c)}{\Delta} = \frac{1}{4} = tan\frac{A}{2}

So,

tan\ A = \frac{8}{15}

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

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