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JEE MainMathematicsModerate

In
a ΔABC, if b=2,c=
3\sqrt{3} and ∠A=π6\angle A = \frac{\pi}{6}, then the
value of R is

Show answer and solution
cosπ6=b2+c2−a22bc=32cos\frac{\pi}{6} = \frac{b^{2} + c^{2} - a^{2}}{2bc} = \frac{\sqrt{3}}{2}
⇒\Rightarrow a = 1
2R=asinA2R = \frac{a}{sinA} ⇒\Rightarrow R = 1

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

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