Question bank/JEE Main/Mathematics

JEE MainMathematicsEasy

In Δ\DeltaABC with usual notation, let
∠A=36∘,∠B=54∘ \angle A = 36^{\circ},\angle B = 54^{\circ}\ and ∠C=90∘\angle C = 90^{\circ}.
If r is the inradius and R is the circumradius of
Δ\Delta; then
(a+br+R)\left( \frac{a + b}{r + R} \right) is equal to.

Show answer and solution
Use r = (s - c) tanC2tan\frac{C}{2} = s - c
R=c2R = \frac{c}{2} (∵\because right angle triangle)
a+br+R=a+bs−c+c2=a+b(a+b2)=2\frac{a + b}{r + R} = \frac{a + b}{s - c + \frac{c}{2}} = \frac{a + b}{\left( \frac{a + b}{2} \right)} = 2

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.