Length of two sides of a triangle are 2 and and angle between the sides is , then circumradius of the triangle is

JEE MainMathematicsModerate

Length of two sides of a triangle are 2 and $\sqrt{3}$ and angle
between the sides is $\frac{\pi}{6}$ , then circumradius of the triangle
is

Show answer and solution

cos\frac{\pi}{6} = \frac{4 + 3 - a^{2}}{2 \cdot (2)(\sqrt{3})} \Rightarrow \frac{\sqrt{3}}{2} = \frac{7 - a^{2}}{4\sqrt{3}}

\Rightarrow

a = 1

R = \frac{a}{2sinA} = \frac{1}{2sin\frac{\pi}{6}} = 1

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

Scan any doubt from your notes and get a whiteboard explanation.