Question bank/JEE Main/Mathematics
JEE MainMathematicsModerate
The sides of the ABC satisfy the relations a + b - c =
2 and 2ab - c^2 = 4, x is the area of then the value of x^6
is
Show answer and solution
a + b - c = 2
a^2 + b^2 + c^2 + 2ab - 2bc - 2ac = 4 = 2ab - c^2
(b - c)^2 + (a - c)^2 = 0
a = b = c
a = 2
a^2 + b^2 + c^2 + 2ab - 2bc - 2ac = 4 = 2ab - c^2
(b - c)^2 + (a - c)^2 = 0
a = b = c
a = 2
Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx
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