If in a sinC = 2secA - tanA and , then is equal to

JEE MainMathematicsTough

If in a $\ \Delta ABC,\sqrt{3}$ sinC = 2secA -
tanA and $\angle C = \lambda^{\circ}$ , then $\frac{\lambda}{18}$ is
equal to

Show answer and solution

\sqrt{3}cosAsinC = 2 - sinA \Rightarrow \angle

A must be
acute
Now maximum value of

\sqrt{3}\cos A + \sin A = 2\ \Rightarrow

sin C =
1

\Rightarrow \angle C = 90^{\circ}

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

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