Question bank/JEE Main/Mathematics

JEE MainMathematicsModerate

In a triangle ABC, if a: b: c = 3: 7: 8, then Rr\frac{R}{r}
is equal to

Show answer and solution
a = 3x, b = 7x, c = 8x
S=3x+7x+8x2=9xS = \frac{3x + 7x + 8x}{2} = 9x
Δ=9x(6x)2x(x)=63x2\Delta = \sqrt{9x(6x)2x(x)} = 6\sqrt{3}x^{2}
R=abc4Δ=3×.7×.8x4.63x2=7x3R = \frac{abc}{4\Delta} = \frac{3 \times.7 \times.8x}{4.6\sqrt{3}x^{2}} = \frac{7x}{\sqrt{3}}
r=ΔS=63x29x=23x3r = \frac{\Delta}{S} = \frac{6\sqrt{3}x^{2}}{9x} = \frac{2\sqrt{3}x}{3}
Rr=(7x3)(23x3)=72\frac{R}{r} = \frac{\left( \frac{7x}{\sqrt{3}} \right)}{\left( \frac{2\sqrt{3}x}{3} \right)} = \frac{7}{2}

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

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