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JEE MainMathematicsEasy

In a Δ\DeltaABC, if 2a^2 + 4b^2 + c^2 = 4ab + 2ac, then the
triangle is

Show answer and solution
a^2 - 4ab + (2b)^2 + a^2 - 2ac + c^2 = 0 ⇒\Rightarrow (a
- 2b)^2 + (a - c)^2 = 0 ⇒\Rightarrow a = 2b & a = c

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

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