In an obtuse angle triangle ABC, a = and R = , then angle C is

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In an obtuse angle triangle ABC, a =
$\sqrt{3} + 1,B = \frac{\pi}{3}$ and R = $\sqrt{2}$ , then angle C is

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sinA = \frac{a}{2R} = \frac{\sqrt{3} + 1}{2\sqrt{2}} \Rightarrow A = \frac{7\pi}{12} \Rightarrow C = \pi - A - B \Rightarrow C = \frac{\pi}{12}

Source: Grass-G / M-24 Mathematics Paper 31 Dec.docx

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