Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateCircles

The equation of circle with origin as the centre and passing
through vertices of an equilateral triangle whose median is of length

3a, is

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ftl yEckbZ 3a gS]

Show answer and solution
sin⁡30∘=ar⇒r=2a\sin 30^{\circ} = \frac{a}{r} \Rightarrow r = 2a

Source: Grass-G / M-25 Mathematics Paper 7 Jan.docx

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