Question bank/JEE Main/Mathematics

The vertices of a triangle are
$A( - 1, - 7),B(5,1)\ and\ C(1,4)$. The equation of bisector of
$\angle ABC$ is
f=Hkqt A(-1, -7), B(5, 1) vkSj C(1, 4) gS] rc
$\angle ABC$

A$x - 7y = 2$B$x - 7y + 2 = 0$C$2x = y$D$2x + 3y = 0$

Show answer and solution▾

$y - 1 = \frac{1}{7}(x - 5)$

Source: Grass-G / M-25 Mathematics Paper 7 Jan.docx