Question bank/JEE Main/Mathematics

Let $x^{2} + y^{2} - 4x - 2y - 11 = 0$ be a circle. A pair of
tangents from the point (4, 5) with a pair of radii form a quadrilateral
of area (in sq. units)
ekuk $x^{2} + y^{2} - 4x - 2y - 11 = 0$,d o`Ùk gSA fcUnq (4, 5)

A1B2C3D8

Show answer and solution▾

$PA = \sqrt{4^{2} + 5^{2} - 16 - 10 - 11} = 2$

Source: Grass-G / M-25 Mathematics Paper 7 Jan.docx