Question bank/JEE Main/Mathematics

JEE MainMathematicsEasyStraight Lines

Find the number of the values of k for which the lines
kx+2y+2=0,2x+ky+3=0,3x+3y+k=0kx + 2y + 2 = 0,2x + ky + 3 = 0,3x + 3y + k = 0 are concurrent
k dk eku Kkr dhft, tcfd js[kk,sa

kx+2y+2=0,2x+ky+3=0,3x+3y+k=0kx + 2y + 2 = 0,2x + ky + 3 = 0,3x + 3y + k = 0 laxkeh

Show answer and solution
$\Delta = 0 \Rightarrow \left| \begin{matrix}
2\ \ \ \ k\ \ \ \ 3 \\

3\ \ \ \ 3\ \ \ \ k \\

k\ \ \ \ 2\ \ \ \ 2

\end{matrix} \right| = 0 \Rightarrow k^{3} - 19k + 30 = 0 \Rightarrow k = 2,3, - 5$

For k = 2, lines are parallel. k = 2

Source: Grass-G / M-25 Mathematics Paper 7 Jan.docx

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