Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateCircles

If the tangent at point PP on circle
x2+y2+6x+6y=2x^{2} + y^{2} + 6x + 6y = 2meets straight line 5x−2y+6=05x - 2y + 6 = 0 at
point Q on y-axis then find length PQ;fn o`Ùk
x2+y2+6x+6y=2x^{2} + y^{2} + 6x + 6y = 2 ds fcUnq PP ij
ljy ij fcUnq Q ij feyrh gS] rc PQ

Show answer and solution
QP=02+32+18−2=5QP = \sqrt{0^{2} + 3^{2} + 18 - 2} = 5

Source: Grass-G / M-25 Mathematics Paper 7 Jan.docx

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