Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateStraight Lines

The new position of the point (1, 2) under rotation through an
angle of 90º about the origin in anticlockwise direction is
fcUnq (1, 2) fLFkfr lfn'k gksxsa tcfd bl fcUnq dks ewy fcUnq
okekorZ fn'kk

Show answer and solution
h=5cos(90∘+θ)=−5sinθ=−2h = \sqrt{5}cos\left( 90^{\circ} + \theta \right) = - \sqrt{5}sin\theta = - 2
k=5sin(90∘+θ)=5cosθ=1k = \sqrt{5}sin\left( 90^{\circ} + \theta \right) = \sqrt{5}cos\theta = 1

Source: Grass-G / M-25 Mathematics Paper 7 Jan.docx

More JEE Main questionsChapter practice

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.

Scan a doubtView plans