Question bank/JEE Main/Mathematics

Equation of a circle of radius 2 and touching the circles
$x^{2} + y^{2} - 4|x| = 0$ is
f=T;k 2 ds o`Ùk dk lehdj.k gksxk tks o`Ùkksa
$x^{2} + y^{2} - 4|x| = 0$

A$x^{2} + y^{2} \pm 4\sqrt{3}x + 8 = 0$B$x^{2} + y^{2} \pm 4\sqrt{3}y + 8 = 0$C$x^{2} + y^{2} \pm 4\sqrt{3}y - 8 = 0$D$x^{2} + y^{2} \pm 2\sqrt{3}y + 2 = 0$

Show answer and solution▾

$C(0,k)\& C_{2}(2,0)$
${CC}_{2} = 4 \Rightarrow \sqrt{4 + k^{2}} = 4 \Rightarrow k = \pm 2\sqrt{3}$

Source: Grass-G / M-25 Mathematics Paper 7 Jan.docx