Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateEllipse

Let (m, n) to be a point from which two perpendicular tangents
can be drawn to the ellipse

4x^2 + 5y^2 = 20. If E=4m + 3n, then

Show answer and solution
Here, (m, n) lies on director circle of given ellipse
(x25+y24=1)\left( \frac{x^{2}}{5} + \frac{y^{2}}{4} = 1 \right);gka (m,n) nh?kZo`Ùk
(x25+y24=1)\left( \frac{x^{2}}{5} + \frac{y^{2}}{4} = 1 \right) o`Ùk ij
fLFkr

∴(m2+n2=5+4)⇒ \therefore\left( m^{2} + n^{2} = 5 + 4 \right) \Rightarrow \ Director
circle fu;ked o`Ùk
∴m=3cosθn=3sinθ\therefore m = 3cos\theta n = 3sin\theta
E=12cosθ+9sinθE = 12cos\theta + 9sin\theta
−(12)2+92≤E≤(12)2−92- \sqrt{(12)^{2} + 9^{2}} \leq E \leq \sqrt{(12)^{2} - 9^{2}}
−15≤E≤15- 15 \leq E \leq 15

Source: Grass-G / M-26 Mathematics Paper 1 15 Jan.docx

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