Question bank/JEE Main/Mathematics

JEE MainMathematicsEasyProperties of triangle

In an equilateral ΔABC,r,R,r1\Delta ABC,r,R,r_{1}, form (where symbols
have usual meanings)

leckgq f=Hkqt
ΔABC,\Delta ABC, r,R,r1r,R,r_{1},

Show answer and solution
a=b=c⇒s=3a2a = b = c \Rightarrow s = \frac{3a}{2}
r=(s−a)tanA2=a23r = (s - a)tan\frac{A}{2} = \frac{a}{2\sqrt{3}}
R=abc4Δ=a33a2=a3=2a23R = \frac{abc}{4\Delta} = \frac{a^{3}}{\sqrt{3}a^{2}} = \frac{a}{\sqrt{3}} = \frac{2a}{2\sqrt{3}}
r1=StanA2=3a23r_{1} = Stan\frac{A}{2} = \frac{3a}{2\sqrt{3}}
∴r,R,r1, form an AP\therefore r,R,r_{1},\ form\ an\ AP

Source: Grass-G / M-26 Mathematics Paper 1 15 Jan.docx

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