JEE MainMathematicsEasyConic Sections

Find the latus rectum of the conic (3x+4y-4)^2=4(4x-3 y+1).
'kkado (3x+4y-4)^2=4(4x-3 y+1)

Show answer and solution

\left( \frac{3x + 1y - 1}{5} \right)^{2} = \frac{4}{5}\left( \frac{4x - 3y + 1}{5} \right)

L \cdot R = \frac{4}{5}

Source: Grass-G / M-26 Mathematics Paper 1 15 Jan.docx

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