Question bank/JEE Main/Mathematics
JEE MainMathematicsModerateCircles
One of the diameter of the circle circumscribing the rectangle
ABCD is 4y = x + 7. If A and B
are the points (-3, 4) and (5, 4) respectively, then the area of
rectangle is
ifjxr o`Ùk dk,d fcUnq
(-3,4)rFkk (5,4)gS rc =Qy
Show answer and solution
Mid point of AB = (1, 4)
The equation of perpendicular bisector of AB is x = 1 center of the
circle is (1, 2) the sides of
rectangle are 8 and 4.
The equation of perpendicular bisector of AB is x = 1 center of the
circle is (1, 2) the sides of
rectangle are 8 and 4.
Source: Grass-G / M-26 Mathematics Paper 1 15 Jan.docx
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